Search results for query: *

Hello EB I have an issue : In my photo website I have created a gallery where I can scroll back or forward my pics and view all the albums, but scrolling the pics already big size. I want to add a div to put on the left handside of the page, where I wish to view all the related thumbs of the...

Thanks Very much!!! Now it works! Really, Thank you! ciao :)

Hello everybody I need to make a link on a php page using php I have this code $result = mysql_query ($sql); while ($row = mysql_fetch_row($result)) { if ( $item == 0 ) { $_firstext = $row[1]; } if ( $item == 0 ) { $_primafoto = $row[0]; } if ( $item == 0 ) { $_primolink = $row[0]; } echo...

Hi I thank you very much for your help. It works The only thing to fix is that thefirst pic, (out of the description counter) miss the description,. I have to fix that thanks !! :)

Hello.:) I got this $sql = "SELECT * FROM notturna ORDER BY descrizione"; $result = mysql_query ($sql); while ($row = mysql_fetch_row($result)) { if ( $item == 0 ) { $_primafoto = $row[0]; } echo "photos[".$item."]=\"notturna/".$row[0].".jpg\";"; $item=$item+1; } } ?> function arrow() {...

Hi billy just solved now . thx for your advice. with this method in xhtml: <img src="notturna/<?php echo $_primafoto; ?>" name="photoslider"> i javscript code, added this: if ( $item == 0 ) { $_primafoto = $row[0]; } thx bye!

Hello I got this script. The proiblem is that when i load the page, it does not appear the first image of the gallery, but it's empty. Due to the fact that in img src="" i don't know which is the correct js code to write. So, the first image is empty. To see the images i have to push the...

Thanks a lot! bye! :)

hi feherke thanks for your help, it works greatly just a question: I am noob and don't know the meaning of this second part of script ==gius.src?su.src:gius.src; If you got time may you exp. the fundamentals? and the ? what it is for? thanks mate, ;) paolo

Hello EB ;) I got this <script type="text/javascript" language="JavaScript"> if (document.images) { var su = new Image(); // for the inactive image su.src = "photo1.jpg"; var gius = new Image(); // for the active image gius.src = "photo.jpg"; } function act() { if (document.images)...