can you elaborate on that please - I struggle to understand !!!!
can the image be delivered via qrystring and use database only as this is the important bit - no server or hosting to be done .....
I want to check a field and if this field contains value then move this value to s field in the table and update.
I would like to build this in BEGIN .... END And incorprate an IF .. How do I do it ?????/
e.g name1 in table called NAMES
newname - a variable in the script
If newname=blanks...
I have created a imagetest table in phpmyadmin and added a image to it, i can view the first image however when i add another image i am having trouble viewing the 2nd image ie 'nokia' can anyone help? my code is as follows only OutBack image is displayed:
<?php
$DB_Host = "xxxxxx"...
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