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DateDiff Expression in Access 2003-Simple?
Running access 2003 and want to have field value (3) produce the result (in days) between field dates 1 and field dates 2. The expression I've used is: =DateDiff("d",[field1],[field2]) All I get in field 3 is a zero. I've tried different variations of the above expression such as "d", or no...- CEF2007
- Thread
- Replies: 1
- Forum: Microsoft: Access Queries and JET SQL
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Very easy I suspect but driving me nuts--DateDiff
Running access 2003 and want to have field value (3) produce the result (in days) between field dates 1 and field dates 2. The expression I've used is: =DateDiff("d",[field1],[field2]) All I get in field 3 is zero. I've tried different variations of the above expression such as "d", or no "'s...- CEF2007
- Thread
- Replies: 2
- Forum: -General database discussion
