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Local Static variables and cout
ok, it just seems wierd that the operator is evaluated left-to-right, but the functions aren't evaluated in that order.- tavianator
- Post #3
- Forum: Microsoft: Visual C++
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Local Static variables and cout
could someone please explain to me why this code produces 1: 3 2: 2 3: 1 as-is, and 1: 1 2: 2 3: 3 when uncommented? int foo() { static int i = 0; return ++i; } int main(int argc, char* argv[]) { std::cout << "1: " << foo() << std::endl//; /*std::cout*/ << "2: " << foo() <<...- tavianator
- Thread
- Replies: 4
- Forum: Microsoft: Visual C++
