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What does this line do?
I've got the idea now. It is not shifting the actual value but the target. so 0001>>3 would be 0 at the first and adding it with 1. -
What does this line do?
i believe l will be 0 for any value of i and j becuase for example if i= 00011 (3) j=00001 (1) then 3 right shift will do i=11000 j=01000 and & with 1 will do i=0 j=0 and xor 0=l I don't understand why using this rather than computational speed up. is there any equivalent ordinary formula. I... -
What does this line do?
Could you explain what does below line do to l. For example if i=0 and j=0 what's the value of l. l = ((i>>3)&1) ^ ((j>>3)&1) ;
