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collecting exit code on variable
why red echo does not return '2' while green one does? $ unset C $ { ls missing 2>&1;C=$?; } ls: 0653-341 The file missing does not exist. $ echo $C 2 $ unset C $ { ls missing 2>&1;C=$?; }|sed s/^/error:\ /g error: ls: 0653-341 The file missing does not exist. $ echo $C $- yesornot
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- Replies: 3
- Forum: UNIX Scripting
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awk simple code
just want someone confirm there is no error in my micro awk code below * if given on "f" not exists in input, then print not exists * if given on "f" exists and given on "s" is greater than number in file a, print 'too small' $ cat a 200 /f1 300 /f2 500 /f4 $ awk -vf=/f5 -vs=400 'BEGIN {c=0}... -
getting rid of tailing zeroes in floating number
$ echo 4000.24320000000000223230000|sed s/0*$//g 4000.2432000000000022323 (ok) $ echo 4000.0000|sed s/0*$//g 4000. (not ok - expected 4000) $ echo 4000|sed s/0*$//g 4 (not ok - expected 4000)- yesornot
- Thread
- Replies: 2
- Forum: UNIX Scripting
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awk syntax error
hi expected is to print single 'obsolete' or single 'input error' text (when conditions are met), but for the first if condition print (in this example): 1 3 fields, a>10 2 3 fields, a>10 what is wrong with "exit" in code below? # echo "a b c\na b c"|awk -va=11 '{if (NF==3&&a>10) print NR,NF"...
