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can any body give me the idea to solve this problem, not the whole answer.thanks, Use a matrix represents an island surrounded by water. Two bridges lead out of the island. A mouse is placed on the black square. Write a program to make the mouse take a walk across the island. The mouse is...

is there any possibility to convert a char to a char array example : here is char a ='163'; char data[16]; i want to input the value of 'a' to 'data' as data[0]='1' data[1]='6' data[2]='3' data[3]='\0'

i want to pass two characters("6","8") into a function which will convert this two chars into integers and add these two integers(6+8=14) after that it will change the value (int 14) into char (char "14") and returns the char. can anybody help me please ??

what is wrong with this code? its not working . can anybody explain in detail please ??? ____________________________ #include <stdio.h> #include<stdlib.h> #include<string.h> void newStrCpy(char* q, char* p); int main (void) { char *q = "MANICHANDRA"; char *p ...

output of this _____________________ int main() { char s[]="MANI"; char *p; p=s; *p = "CUCKOO"; //*(p+1)='C'; //*(p+2) = 'B'; //*(p+3) = 'D'; printf("%s\n",s); printf("%s\n",p); return 0; } ____________________________ is eANI eANI y can't...

why can't we do this ?? int main() { char *p="MANI";; *(p+1)='C'; *(p+2) = 'B'; *(p+3) = 'D'; printf("%s\n",p); return 0; } when we can do this .. int main() { char s[]="MANI"; char *p; p=s; *(p+1)='C'; *(p+2) = 'B'; *(p+3) = 'D'...

int main() { char *p="MANI"; char *q; printf("%c %c %c %c\n",'M','A','N','I'); printf("%d %d %d %d\n",'M','A','N','I'); printf("%d %d %d %d %d %d %d\n", *p,*(p+1),*p+1,*(p+2),*p+2,*(p+3),*p+3); printf("%c %c %c %c %c %c %c\n"...