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  1. beardown

    awk print records with column is not blank

    how to find/print all records that are not blank in column 2 it must be some variation of this # delete ALL blank lines from a file (same as "grep '.' ") awk NF awk '/./'
  2. beardown

    awk compare column with date format

    I have this code to compare columns 1 and 10 between file1 and file 2 and give me all records that match column 1 but dont match column 10 However column 10 is date format mm/dd/yy and awk cant read it and compare ...i tried CODE awk < file1 -F~ '{print $10}' CODE and it gave blank screen...

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