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Using Variables in Query
Thanks for the explanation bborissov, I understand. Thanks, --Mark- Lrnmore
- Post #3
- Forum: Microsoft SQL Server: Programming
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Using Variables in Query
Hello, I have a question regarding using variables. My environment is SQL Server 2005. I know the variable is set because it only breaks the query if I use it in certain areas. Can someone point out my error? USE SampleCode Declare @myTableName varchar(45) Set @myTableName = 'TestTable'; IF...- Lrnmore
- Thread
- Replies: 2
- Forum: Microsoft SQL Server: Programming
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AJAX-type form submission
You'll need to "open" the request first(before setting header): <script type="text/javascript"> var xmlhttp function loadXMLDoc(url) { // code for Mozilla, etc. if (window.XMLHttpRequest) { xmlhttp=new XMLHttpRequest() xmlhttp.open("POST",url,true)...- Lrnmore
- Post #3
- Forum: Javascript
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Ajax
If you don't have conditions that you have to check after each function you could create the array and then use setTimeout. var myDel = 'f1|f2|f3'; function doFunctions(){ var tmp = new Array(); tmp = myDel.split("|"); tmp = tmp.join('();') + '()'; setTimeout(tmp, 50); } Thanks, --Mark- Lrnmore
- Post #2
- Forum: Javascript
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IE 6.02 throwing a syntax error - Am i missing something
Dave is dead on... Change the method to "post" and it works fine. I'm guessing that comment you're formatting is too much.. Good Job Dave. Thanks, --Mark- Lrnmore
- Post #11
- Forum: Javascript
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IE 6.02 throwing a syntax error - Am i missing something
Unfortunately, I don't have time to complete the mission. But I can pass on a waypoint: If you comment this line it works: function TestDataCheck(feedback) { var pagecounter_passed = parseInt(document.uspsfeedback.pagecounter.value); var pagecounter_passed = pagecounter_passed + 1...- Lrnmore
- Post #10
- Forum: Javascript
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mouseover only works once
This will make it work in both FF and IE: Add these classes to your style sheet: .hide_quote { display: none; } .show_quote { display: block; position: absolute; top: 18px; left: 10px; width: 125px; height: 70px; border: 1px solid #000; background-color: #ffe; color...- Lrnmore
- Post #6
- Forum: Javascript
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mouseover only works once
I can tell you one thing that I've run across with the combination of IE and XMLHttpRequest is a cache issue. Nothing may be wrong with your code, IE may be stubbornly denying the new request. Check out this FAQ and especially the "wiki" link at the end. AJAX I don't see where you are setting...- Lrnmore
- Post #4
- Forum: Javascript
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How to in PHP or JS? Don't know???
Maybe this will give you a start: AJAX FAQ Thanks, --Mark -
AJAX and PHP
...mkSel.html <html> <head> <title>AJAX Example</title> <script type="text/javascript"> //global variable var selArr = new Array(); /*** from http://jibbering.com/2002/4/httprequest.html an article by Jim Ley***/ var xmlhttp /*@cc_on @*/ /*@if (@_jscript_version >= 5) try... -
Check to see if a form element exists
Hi Slippenos, If you notice there is no form field 'EstimateStatusB' in the above example. That is what the first part of our 'if' does. (Makes sure there is a form field with that name before testing the value.) if(form.elements['EstimateStatusB'] && form.elements['EstimateStatusB'].value...- Lrnmore
- Post #7
- Forum: Javascript
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Ajax problem
...padding: 0px; margin: 0px; } </style> <script type="text/javascript" SRC="js/ajax.js"></script> <script type="text/javascript"> <!-- /* simpleFindObj, by Andrew Shearer Efficiently finds an object by name/id, using whichever of the IE, classic Netscape, or Netscape 6/W3C DOM methods is...- Lrnmore
- Post #6
- Forum: Javascript
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Check to see if a form element exists
Is there any reason you can't use the element name like so: <script type="text/javascript"> function ckForm(form){ if(form.elements['EstimateStatus'] && form.elements['EstimateStatus'].value == 'Nothing'){ alert('Your Note'); return false; } if(form.elements['EstimateStatusB'] &&...- Lrnmore
- Post #5
- Forum: Javascript
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Check to see if a form element exists
Do your form fields have their own id's? Are they unique? You are pretty close with the above attempt: <script type="text/javascript"> var arr = ['t1','t2']; function ckFields(){ for(var j = 0; j < arr.length; j++){ if(document.getElementById(arr[j]) != undefined)...- Lrnmore
- Post #2
- Forum: Javascript
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Ajax problem
...<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN"> <html> <head> <title></title> <script type="text/javascript"> var xmlhttp /*@cc_on @*/ /*@if (@_jscript_version >= 5) try { xmlhttp=new ActiveXObject("Msxml2.XMLHTTP"); } catch (e) { try { xmlhttp=new...- Lrnmore
- Post #2
- Forum: Javascript
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Convert br tag to line break?
Maybe this will give you a start: <?php $str = "This is a sting with a br tag.<br />And then we have a <p> tag and a </p> tag."; $str = str_replace("<br />", "\n", $str); $str = str_replace("<p>", "\n\n", $str); $str = str_replace("</p>", "\n\n", $str); echo "<pre>"; echo $str; echo "</pre>"... -
load image last?
litton1, The body "onload" event will work for this: <html> <head> <title></title> <script type="text/javascript"> function loadImg(){ var loadedImg = new Image(); loadedImg.src = "http://www.google.com/intl/en/images/logo.gif"; var Img = document.getElementById('pic'); Img.src =...- Lrnmore
- Post #2
- Forum: Javascript
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need help using javascript for the first time
Form's have an "onreset" event handler. Add this to your opening form tag: onreset="initForm()" And this function: function initForm(){ var trows = document.getElementsByTagName('tr'); allBoxes = 0; for(var j = 0; j < trows.length; j++){ (trows[j].className == 'picked')...- Lrnmore
- Post #19
- Forum: Javascript
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Need a Simple Link Counter
You can incorporate php and javascript like this: count.html <html> <head> <title>Counter Test</title> <style type="text/css"> .count { width: 50px; font_family: verdana; font-size: 24px; color: #00FF40; background: #000000; text-align: center...- Lrnmore
- Post #4
- Forum: Javascript
