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Yeeeaaa. I found the solution to my own problem. You have to call the base call like this. I forgot the () the first time. Thanks for the help.. Mystats::operator =(const Mystats &rhs) { // Base class operator= stats::operator = ( rhs ); // This class Operator= w=rhs.w; }

I have a subroutine that does this. Of course, I got this somewhere else, but I don't remember where. const char * GetFileName(const char *pszPathName ) { static CString STmp = pszPathName; STmp.MakeReverse(); STmp = STmp.SpanExcluding("\\"); STmp.MakeReverse(); return STmp; }

Thank you chpicker for your response, but your code does not use the operator= function, but a predefined copy constructor which is a bit copy of the original object. If you change your line of code Mystats Newstat=mystat; To Mystats Newstat; Newstat=mystat; You will notice that the...

Thanks Ian for your quick responce. I have done that before, but I can seem to get the call correct with a operator function. Any ideas.. Thanks again..

I have two classes, one is the base class of the other. I would like call “operator = “ from the base class in addition to the new “operator =”. I know I am missing something simple, but I don’t know what. class CAge { public: CAge(); ~CAge(); Cage & operator = (CAge &catmp) {...