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you could also try: <img src='image1.gif' style='position:absolute; left:30px; top:20px;'> <img src='image2.gif' style='position:absolute; left:40px; top:30px;'> this gives you more freedom in howmuch the images will overlap each other. the top- and left-attributes give the distance from the...

The easiest thing to do is read the data into a ByteBuffer (java.nio.ByteBuffer, as of J2SDK 1.4.0). example: int datasize = <lengthOfInputData>; ByteBuffer bb = ByteBuffer.allocate(datasize); bb.order(ByteOrder.LITTLE_ENDIAN); then you use bb.putInt() or bb.put() to fill the ByteBuffer with...

The method &quot;public String[] split(String regex)&quot; has been introduced with Java 1.4. Type &quot;java -version&quot; in a console window, the output should be something like java version &quot;1.4.0&quot; Java(TM) 2 Runtime Environment, Standard Edition (build 1.4.0-b92) Java...

There is no standard class to this, but it's actually fairly easy to write your own class to this. All you need to do is get the specs for the different filetypes (bmp, gif, jpg, png) and locate the position of the height and width information in a file's structure. For bmp generated with...

Sun calls the method of joining 2 strings concat(), which has been available since atleast jdk1.1.4, the first jdk I used in 1998. e.g: String s1 = &quot;s11111&quot;, s2 = &quot;s22222&quot;; String s3 = s1.concat(s2); System.out.println(s3); will output s11111s22222

Your source wouldn't even compile, because access to a private variable is not allowed from outside classes. Anyway, v1 is not equal to v2, because you're comparing objects and not variables. the object name in the jvm of v1 is Value@601bb1 and of v2 is Value@ba34f2. As you can see, thes...

You could also try using the classic DOS command &quot;tree&quot;. Start a command prompt, and type &quot;tree c:\ /f /a > ctree.txt&quot; (w/o quotes). This will output a tree like structured ascii text file named ctree.txt into your current directory.