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Hi, I have a dialog-based MFC application, which compiles w/out error, but yields an unhandled exception in C:\...\MFC\SRC\WINCORE.CPP when i try to run it, as shown in the code below. What could be the reason for this? How do i correct it? HWND hWnd = ::GetDlgItem(m_hWnd, nID); if (hWnd !=...

...= {0}, C[size],c,d; double PI = 3.141592653589793238462643383279502884197; void rah(double C[]) { for (int i=0;i<size;i++) { A[i] = sqrt(10*i); B[i] = 2*PI*i; C[i] = A[i]*B[i]; } } double test()//how do i write this correctly? { rah(C); d = PI * rah(C[5]); } int main(int...

Thanks a lot...6. is real humour...tells u how "cautious" im thinking...lol!

...code: double vargm() { double h_x,h_y; lagh = sqrt(pow(hx,2)+pow(hy,2)); if (t == 0 && p == 0) { if (lagh<ay) //lagh/ay<1 { var1 = 1.5*sqrt(pow(lagh/ax,2)); var2 = 0.5*pow(pow(lagh/ax,2),3); y_1 = var1 - var2; } else { y_1 = 1; } if (hx/ax<1) { var1 =...

Salem, >>Thanks a lot guys. I really appreciate it. B4 I saw Salem's post, I'd already implemented this formulation, which runs consistently with Excel/hand calculations for the matrix multiplication.<< My next implementation was created b4 i saw your post. i was in the process of posting that...

...angles to radians, acceptable in C++ //--------------------------------------------------------- //Dip Angle,p double a(double p) { d11 = cos((p*pi)/180); return d11; } double b(double p) { d13 = -1*sin((p*pi)/180); return d13; } double c(double p) { d31 = sin((p*pi)/180); return d31...

That was a typo. PI wasn't my problem anyway...and frankly, i don't need such high accuracy for PI... double PI = 3.141592653589793238462643383279502884197; is not necessary for me. but thanks for pointing it out.

...angles to radians, acceptable in C++ //--------------------------------------------------------- //Dip Angle,p double a(double p) { d11 = cos((p*pi)/180); return d11; } double b(double p) { d13 = -1*sin((p*pi)/180); return d13; } double c(double p) { d31 = sin((p*pi)/180); return d31...

...angles to radians, acceptable in C++ //--------------------------------------------------------- //Dip Angle,p double a(double p) { d11 = cos((p*pi)/180); return d11; } double b(double p) { d13 = -1*sin((p*pi)/180); return d13; } double c(double p) { d31 = sin((p*pi)/180); return d31...

New Problem: Now I'm doing the multiplication, where I'm trying to multiply the arrays in this order: lambda_array*dip_array*azim_array*r_array what am i doing wrong? all my values in the final range array, fr_array are all zero, which shouldn't be the case... Here's the code. // Q2_new.cpp...

Ok....I moved the initialization to after I called the functions, not before. So the arrays are reading correctly now. This was the problem.

math.h does contain sin() and cos(); and when you do a random check, say cout<<a(p);, i actually get the correct value. but the correct values are not turning up in my arrays. Please check and see. Why is this?

...angles to radians, acceptable in C++ //--------------------------------------------------------- //Dip Angle,p double a(double p) { d11 = cos((p*pi)/180); return d11; } double b(double p) { d13 = -1*sin((p*pi)/180); return d13; } double c(double p) { d31 = sin((p*pi)/180); return d31...

...to convert the angles to radians, acceptable in C++ //--------------------------------------------------------- double rad_t(double t) { theta = (t*pi)/180; return theta; } double rad_p(double p) { phi= (p*pi)/180; return phi; }...

I thought it would be okay, since the prototype for the ei function is: double ei(double x[10000]), which passes an array to the ei function.

Hi, the ffg code gave the ffg 2 errors:'ei':cannot convert parameter 1 from double to double[] on both lines * and ** in the code below: #include <math> #include "stdafx.h" #include <fstream> #include <iomanip> #include <iostream> using namespace std; double...

...double t[50],qsf[50],alpha,x[50],EI[50],beta[50],pd[50],pwf[50]; double time_hr() { double N=49.0; for (int i=0;i<50;i++) { t[i] = 0.01*exp((i/N)*log(200/0.01)); } return t[i]; } //In the Presence of Wellbore Storage double wbs() { a0 = -0.57721566; a1 = 0.99999193; a2 =...

timmay3141, thank you so much. i'm indeed grateful...this is the solution i didn't c. many thanks again!

...double t[50],qsf[50],alpha,x[50],EI[50],beta[50],pd[50],pwf[50]; double time_hr() { double N=49.0; for (int i=0;i<50;i++) { t[i] = 0.01*exp((i/N)*log(200/0.01)); } return t[i]; } int main(int argc, char* argv[]) { // printf("Hello World!\n"); ofstream outputdeck...

Thanks, timmay3141 and globos; I eventually wrote the integral thus, but have a problem calling it: double* function(double *p,double *func,int nSize,CKuchukDlg *pDialog); void qgaus(double *ans, int nSize, CKuchukDlg *pDialog) { enum{nSize = 6}; //elements of the integral double xr,xm,dx...