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AWK isn't best used to do "inplace" substitutions in files. The closest to that would be something like redirecting the output to a tmp file, and then over-write the original... #!/bin/bash # awk.sh infil="./awk.data" awk '/apple/ { gsub(/red/, "blue") } /berry/ { gsub(/yellow/, "green") }1'...

I don't mind helping with scripts, but, I'm not good at teaching or writing books. There are better sources than me to learn from. Starting with the command line, there is a lot of help and documentation at hand. @commandline Type: help help man man info <command> Tutorials...

You could use grep, sed, or awk to achieve this... Sed: sed 's/.*\(g.*\)$/\1/g' gg.data | sort -V Awk: awk 'match($0,/g.*$/) {print substr($0,RSTART,RLENGTH)}' gg.data | sort -V output: g1s1 g4s2 g5s1 g15s6 thread80-1459823

I have no idea what I'm doing here. You could try substituting the printf cmd with the nohup call in 2 places... # printf "%s\n" $fld1 nohup ./prox.sh $fld1 > ./prox.log 2>&1 </dev/null & wait

@ pplearnunix46 Just change the output to print fld1. Like so... #!/bin/bash # dates2.sh dat=${1:0:8} tim=${1:(-6):4} fld1=$(date -d "$dat $tim" +'%Y%m%d%H%M%S') printf "%s\n" $fld1 while [ $fld1 -lt $2 ] do fld1=$(date -d "$dat $tim + 15 minutes" +'%Y%m%d%H%M%S') printf "%s\n"...