I've already tried that:
<xsl:template match="show">
<xsl:copy-of select="./*"/>
</xsl:template>
but the system gives me the following message
"the key word xsl:copy-of can't be used here".
I don't know why???
(Thanks MrTom)
hi, I have a problem, I've got a xml file that contains HTML TAGS. I want show this data like HTML without any XML filter. I'm using tag copy:
<xsl:template match=" //show//* | //show//text()">
<xsl:copy >
<xsl:apply-templates />
</xsl:copy>
</xsl:template>
But attributes...
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