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print the last field of a record using awk
Hi, My file looks something like the following /data/udb/sync/exp/hrzsync.exp.1 /data/udb/sync/exp/hrzsync.exp.2 /data/udb/sync/exp/hrzsync.exp.3 etc............ I need to print the last field (FS="/") ie just the file names, removing the preceeding full path so that my output is...
