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Write a predicate 'everyother' which will remove every other element .
Thank joel76 i got it. -
Write Prolog code which will perform a postorder traversal
tree constant. Hint: you might use 'univ', or its cousins. ?- postorder(a(b,c,d(e,f,g))). b c e f g d a true Hi , I am trying this problem but , the output is undefined predicate postorder. I think i wrote correctly but, it is not working. postorder(void,[])... -
Create a binary predicate called 'square' which will square each
Hey ductiletoaster how did u try ? did u check whether the element is integer or not. -
Write a predicate 'everyother' which will remove every other element .
Write a predicate 'everyother' which will remove every other element in a list, starting with the second element. List length can be odd or even. e.g. ?- everyother([g,r,o,u,l,l,o,e,r,s,p],L). L = [g,o,l,o,r,p]; i am trying like this remove([_,_],[]). remove([H,H|T],R):-... -
Create a binary predicate called 'square' which will square each
hi, all I got it ...;) -
Write a predicate 'addbubba' which will place 'bubba' after each atom
e.g. ?-addbubba([a,b,c],X). X=[a,bubba,b,bubba,c,bubba] I tried like this.. addbubba([],[]). addbubba([X|Y],[A|B]):- not(integer(X)), isList(Y),A = X,addbubba(Y,B),append(B,'bubba',K). pls help its urgent... -
Create a binary predicate called 'square' which will square each
Create a binary predicate called 'square' which will square each number in a list. This pred. will be shallow. e.g. ?-square([a,[[3]],b,4,c(5),8],X). X=[a,[[3]],b,16,c(5),64] Need help.
