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4 byte integers with gfortran
I have a large legacy code compiled for intel's ifort compiler, and I'm trying to compile it with gfortran. The original code saves unformatted files with 4-byte integers. I need to do the same with gfortran, but the only relevant compiler option I've seen is -fdefault-integer-8, not -4. I'd... -
Divide by zero but never called
Thanks, that trick to compile and link! -
Divide by zero but never called
Also... it gives the same problem without using real(), so if the write line is changed to: write(*,*) 1/b the same error and warning occur. -
Divide by zero but never called
Hello, I'm trying to compile code originally written for intel ifort compiler with gfortan, and I've come across an error that I was able to reproduce with the following small program: program testdivzero implicit none integer a,b parameter (b=0) do a=1,b...
