No that is not a reason I have some minor problems and if you can may be
you could help me because I can not find an answer to this errors. Thanks a lot. I have a problem with a line 57 ("open l_cursor for SQLQuery;") and last line where I have "/". Please help.
Thanks...
I have some minor problems and if you can may be
you could help me because I can not find an answer to this errors. Thanks a lot. I have a problem with a line 57 ("open l_cursor for SQLQuery;") and last line where I have "/". Please help.
Thanks again.
57 PLS-00103...
I have a stored procured in SQL and I need to re-write it for ORACLE 8.
I am new in Oracle and still learning.
Please Help. Thanks a lot.
CREATE PROCEDURE SearchProductCategory
@Product as varchar(50),
@SearchTypeProd as int,
@Category as varchar(50),
@SearchTypeCat as int
AS
declare @SQL as...
Thanks for your help but I still have a problem. I am trying to execute package/Procedure and I am getting an error:
ORA-00604: error occurred at recursive SQL level 1
ORA-01460: unimplemented or unreasonable conversion requested
ORA-06512: at "SYS.DBMS_LOB", line 370
ORA-06512: at...
I've been tring to post same question for a 3rd time and can not get even one
helpfull answer. Please if you do not know do not answer and do not give me
answers like "see this link or that"
I am trying to run SQL statement to update one field with a datatype "clob"
and...
yes, if I make a string 4000 chr it work but how can i saqve 8000 0r 10000 or even more? I need to use clob as a field datatype. I can create a package and pass string of 8000 chr into package but looks like I will have same error that string is too long. How can I insert/update/select value...
I am trying to run SQL statement to update one field with a datatype "clob"
and SQL give me an error "ORA-01704: string literal too long ".
The len of the string I am trying to save is 8336 chr. It could be longer or
shorter depending on a webpage.
If I take only 4000 chr...
I am trying to rur SQL statement to update one field with a datatype "clob" and SQL give me an error "ORA-01704: string literal too long ".
The len of the string I am trying to save is 8336 chr. It could be longer or shorter depending on a webpage.
If I take only 4000 chr...
How can I get a select of 12 month starting with current month down. Example 06/2002, 05/2002,..........08/2001,07/2001
Please help
Thanks for your help
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