Recent content by xmassey

I changed my version of the code slightly so that the only variable that the script needs is which letter/word you want to find (because before it sort of needed to know how many letters/words the array contained (shown by the until ($no == 4);)... #! usr/bin/perl use strict; ##### print...

I used this... #! usr/bin/perl use strict; print "Content-type: text/html\n\n"; my ($tofind, $no, @var); $tofind = 'c'; $no = '0'; @var = ('a', 'b', 'c', 'd', 'e'); do { if (@var[$no] eq $tofind) { $no = $no + 1; print "$tofind is at position $no"; } $no = $no + 1; } until ($no == 4)...

Have you already written some code, because I can think of a few ways to do this, and I was wondering which approach you took

They aren't even encrypted. I don't get why they need to be??? The correct username and password is stored in a text file which is highly secured using htaccess, no one can view the correct username an dpassword

Yes, I meant print "$array"; Thanks

Thank you

I don't know if this helps... I once had a left right scroll bit at the bottom... I had a navigation box on the left, and a main section on the right. By giving the main section a 100% width it made the page had to scroll as much as the navigation was width... I solved it by indenting the text...

Ok maybe I have figured out what you were saying... @array = ('one', 'two', 'three'); $aaa = @array; print "@array"; The output is the number of words the array contains (3)... @array = ('one', 'two', 'three'); $aaa = "@array"; print "@array"; The output is the words the array contains (one...

I can only figure, that if I pass an array onto a scaler, then it counts the number of words the array contains, otherwise if I don't pass it to a scaler it prints the words contained within the array

I read that the \a sounds an alarm (bell). I tried using this script... #! usr/bin/perl use strict; print "Content-type: text/html\n\n"; print "\aHello!\n"; The result is a little square box and the word Hello. Anyone know why I don't get a bell sound>?

Well, no hehe. When the user logs in the first time, when they click login, a hidden field carries the username and password, so once in the admin area, if they click on another button i check if the username and password carried by the hidden field is the same as in the file storing it. This...

Thats really strange. When I first built a user login system using perl, I used a really simple idea, which involved checking to see if the file contained the correct username and password. Below is part of my code... $ausername = param('username'); $apassword = param('password'); $auserpass =...

I was presuming that 1 word was stored in the file. If I'm taking multiple words from a file then I would use split, to split all the words into individual scalers. However you would need to know how many words there are. Is there a way to count the number of words in an array, something like...

ahh, its being blocked out by "~~~~" so i can't see the site.

Ill tell you what, I have a Visual Quick Start guide for PHP and it has lots of examples, including a user authetication system. However, my main script language is perl... I do all the coding, and store all important info like passwords in a text file. I then secure just the text file with...