Recent content by VAMick

This has been great info and a big help to me. I thank you for taking the time to explain it and rewrite my code. I'll give those last suggestions a try to see if they remedy the double emailing issue. At least I'm sending out two quality emails now! haha.

That worked great, except it still sends two emails. Thoughts on that? Btw, was it the fact that my code didn't specify $messsageHeader that it was failing? And thank you!!

I dropped my headers and message code and used yours. First time it didn't send anything but a blank email. then i used part of my code, part of yours. 4 emails. At this point, i'm getting frustrated and have no clue how to get this to work right. What's crazy is it worked just fine on the...

Here you go. http://tek-tips.com/viewthread.cfm?qid=1285570

jpadie, I have worked for hours on the code using your post as a basis and it only got worse. Now it doesn't send the message at all, just a blank email, with the correct To: address, but it sends it 4 times. This is my old code, that works on my Mac email, but not the other clients. It also...

Looks like I was def leaving some code out of the headers. Took me a while to find that posting, but was well worth it. Thanks.

Ok,I've got a dynamically created form that gets emailed to clients as HTML. PHP/Mysql creates it. Worked fine for everyone until we changed hosts and went from PHP4 to PHP5. Now, it works fine on my Mac and one of my clients PC's, but the rest of his staff receive it as raw html code instead...

i just switched hosts, going from php4 to php5 and have a slew of problems with my code now. Can anyone tell me what's going on here? I'm getting a PHP notice error of: PHP Notice: Undefined offset: 1 in /var/www/vhosts/domain.com/httpdocs/folder/file.php on line 76 that points to this code...

Thanks. I didn't realize it was that simple. I guess what confused me about that function was i thought i'd have to put in the code what table it was to look to for the last insert. i guess mysql is smarter than I.

I need to insert data into two tables at the same time from a form for adding new vendors, but I'd like to grab the auto generated ID from the first table and put it in the second table so that they match. Is that even possible and if so, what would the code look like? Thanks. Using php/mysql.

Ok, your version is MUCH better and worked.

Can someone tell me what is wrong with my sql statement below? I keep getting a syntax error. Thanks. SELECT * FROM (SELECT vendorname, SUM(cogs)AS sumcogs FROM spec_registrar WHERE orderdate >="2006/01/01" GROUP BY vendorname )as totals WHERE sumcogs >="10000.00

Ok, stupid mistake, I forgot to upload the lang folder.

I'm giving jpgraph a try for the first time. Went thru the install with everything left at default. Used some sample code from a tutorial over at phpfreaks.com. I'm getting an error message that I don't know how to address. Maybe someone can shed some light? This is the message in my browser...

I started with these two chunks of code... <?php // Note that !== did not exist until 4.0.0-RC2 if ($handle = opendir('/path/to/files')) { echo "Directory handle: $handle\n"; echo "Files:\n"; /* This is the correct way to loop over the directory. */ while (false !== ($file =...