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Recent content by kahleen
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member predicate
Well, I really think that you should try yourself taking little steps to fulfill your goal. Asking some random guy on a forum solve each and every step is neither appropriate for learning, nor rewarding. Rewarding is when you discover by yourself that using this or that condition helps in... -
member predicate
'start_algorithm' ends with a comma. It should end with a dot. So probably Prolog won't even compile your code, you shouldn't try to run it when the compilation reports error, but rather try to fix those errors. -
member predicate
Anyway, I suggest you rely on node IDs for the moment and not names. Let the user enter IDs. From what I see, most of the nodes in your 'leuven.pl' don't have a node_tag with name information. -
member predicate
and how do i replace the node Ids with name of node_tag?" Come on, this is easy. node(16387325, 50.8686270, 4.6984337). node_tag(16387325, 'name', 'Kardinaal Mercierlaan'). If the program expects user input (read(X)) and the user enters 'Kardinaal Mercierlaan', then X would take that... -
Find route in a system
Glad to help. Without that rule, recursivity doesn't end. Prolog will successively shorten the list and will arrive at an empty list and no rule will tell it how to get the minimum out of that list, so it will fail. We have to provide the answer manually when the list gets to be 1-element long... -
Find route in a system
Well, you forgot one min rule. Read the previous post, you will find 3 min rules. 1st step and 2nd step are both mandatory, you only have 2nd step PS: You're Romanian, so this means we're co-nationals :) -
Find route in a system
Post the entire code then ... It works on my machine -
Find route in a system
The only thing I suspect besides a typo is the call to 'link' from the 'route' predicate'. You have something like this: link(Ori, C,_, X), This is a call with 4 parameters. Do you have 'link' facts that take 4 parameters? Because I would say that 'link' should take 3 parameters: first... -
member predicate
Make sure you replaced your original code with the one I provided. 'start_algorithm' should take 1 parameter, like in the last code snippet. The original version had 0 parameters, and that's what's causing the error -
Find route in a system
The same principle applies. 1st step - a list of one element would be something like this: [ [Path, Length] ] ... the minimum of such a list is [Path, Length] In Prolog: minimum([[Path, Length]], [Path, Length]). 2nd step - a list with more than one element would be something like this: [... -
member predicate
Ok, I didn't try on the large 'leuven.pl' file, so maybe it goes on forever because there are many results. Do the following modification to the code, so that Prolog will stop after each solution and print it to you: init :- consult('leuven.pl'), % get the nodes and ways... -
member predicate
Ok, try adding this code in the upper part of the file where you have 'start', 'create_db' and 'process': :- dynamic(edge/3). This way you tell Prolog that it should expect to have some 'edge' clauses asserted dynamically, even though there are none defined explicitly, so it should stop... -
member predicate
You don't need the cut. Those are only due to duplicated edges. Go back to where you have defined the 'process' predicate and modify it like below: process([]). process([_]). process([A, B | Rest]) :- distance(A, B, Dab), % compute distance A - B \+edge(A, B, _), %... -
Find route in a system
Well, if there are 5 solutions to the 'route' predicate, your findall will gather in List their lengths ... so you will get 5 integer in List, you can compute the minimum or do whatever you want with them, but you will not have paths in there. You need to modify your findall to generate not a... -
member predicate
What nodes did you try? Because as I told you, your current algorithm does not take into account that edge(A, B, X) also means edge(B, A, X), so maybe some possibilities are not considered. Make sure that you don't choose nodes that are not connected in your graph, or are connected but only if...
