Recent content by javaken

What if your inputstring is null??? Because it becomes from a object .... java.lang.NumberFormatException: For input string: "null" at java.lang.NumberFormatException.forInputString(Unknown Source) at java.lang.Integer.parseInt(Unknown Source) at java.lang.Integer.parseInt(Unknown Source)

a piece of my code ... XManager is a class which me return a collection Another class use this ....: Collection entries = XManager.INSTANCE.findX(ThingsFrom); Iterator iter = entries.iterator(); while (iter.hasNext()){ object = (Object)iter.next(); Vector row = new Vector()...

Suppose the result of your vector gives you 2 rows .... Is it possible to make 1 string of this result, also if you have 3 rows or more .... I work with a linked list, collection ... Result: one column in my case has 2 or more rows ... 1 2 I want to make of this a string = "1 2 " or "1 2 3...

Is this possible? Thanks

Suppose: you have folowing string of numbers .... "1 2 3 4 5 6 " How to convert it to an integer?? The procedure will also be possible if your string exists of 10 numbers .... "1 2 3 4 5 6 7 8 9 10 " Thanks

Hey, Who can give a simplified version of code to do this? Sorry, but I have lost the key .... °) or in other words I have problems to do this .... Thanks [upsidedown]

Hey, How to clear the contents of a JTextArea??? Thanks [pipe]

Sedj, Thanks for the quick hack .. Greetz [smile]

String s = (String)thingsComboBox.getSelectedItem(); gives an error In class things I have: ID (== int) + thing (==string) = one object object is sitting in my combobox. How can I get the contents of thing1 when item 1 in my comboBox is selected. You to put it in a string??? Thanks ...

Hey, I have following exception : java.lang.ClassCastException I've read a file, and put the values in objects of a class. I've put the objects in a combobox. Now I have a list with items .... that I can select but .... I want to use a selected item, en put it in a string ... How to do...

Suppose you have a class X: class X produce an object exists of 2 elements: ID + Contents ==> each object is formed by this 2 elements ... ==> in code you have 2 classes ... You have following arraylist-output: 4 AAAAAA 4 = ID AAAAAA = element Contents 5...

Your code/solution was very nice Sedj!!!!!! I complete it because it was so nice ! It's above so short. Thanks Sedj!!!! [bigsmile]

Suppose: You have following arraylist-output: 4 AAAAAA 5 ZZZZZZ 2 DDDDDD 1 AAAAAA 3 AAAAAA one row is one object: Questions: how to sort rows on numbers ascending? ==> output = 1 AAAAAA 2 DDDDDD 3 AAAAAA 4 AAAAAA...

This will be something like this ...... Greetings [dazed] /* * Created on 21-mei-2004 * */ import java.io.BufferedReader; import java.io.File; import java.io.FileReader; import java.io.IOException; import java.util.ArrayList; public class ReadingFile { public ReadingFile(String...

In Vb.net = DirectCast ..... In Java ? Thanks!!! [smile]