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Recent content by Dharma1955
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Find 20 random records
I should have said random values.- Dharma1955
- Post #8
- Forum: Business Objects: Crystal Reports 1 Formulas
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Find 20 random records
If you accept that RND() gives a random number the approach I outlined gives 20 unique random numbers.- Dharma1955
- Post #7
- Forum: Business Objects: Crystal Reports 1 Formulas
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Find 20 random records
Add this to your detail section: //@Random_Value Whileprintingrecords Numbervar random If previous {result of RND()}<> { result of RND()} then random_:=random+1 else random:=random Then use a detail suppression formula like this: Previous({result of RND()})={result of RND()} or {@Random_Value}>20- Dharma1955
- Post #5
- Forum: Business Objects: Crystal Reports 1 Formulas
