XSLT to copy all elements and attributes with modifications

Jake32 · Nov 13, 2007

I have an xml source that I would like recreate with some modifications. Specifically, I would like to modify attribute values based on a condition. I'm able to recreate the XML file but it's the modifications that I'm having difficulties with.

For example, based on the xml sample below, if PARA Style = "Section_Title", I would like to:

1) Change the value for the align attribute from "left" to "right" and
2) Change the text from "This is My Title" to "Book Title"

Any help would be greatly appreciated.

My XML file is as follows...

<?xml version="1.0" encoding="UTF-8" standalone="yes"?>

<MYROOT>

<BODY>
<SECTION>
<PARA Style="Section_Title" align="left" emphasis-bold="true">This is My Title </PARA>

<PARA Style="Body" align="left">
<STEXT font="Arial" hidden="true">This is some special text</STEXT>
<LINK Style="Body Text" align="left">

http://www.test.com</LINK>

</PARA>
</SECTION>
</BODY>
</MYROOT>

So far I'm only able to recreate the same XML file using the following XSL

<?xml version="1.0"?>
<xsl:stylesheet version="1.0" xmlns:xsl="

http://www.w3.org/1999/XSL/Transform">

<xsl:template match="*">
<xsl:copy>
<xsl:apply-templates select="@*"/>
<xsl:apply-templates select="*|text()"/>
</xsl:copy>
</xsl:template>

<xsl:template match="@*">
<xsl:copy>
<xsl:value-of select="."/>
</xsl:copy>
</xsl:template>

Thanks.

k5tm · Nov 13, 2007

Have a look at thread426-1376418

Tom Morrison

http://www.liant.com

Jake32 · Nov 14, 2007

Thanks Tom for your help.

I do understand how to copy all elements and text nodes and how to rename an attribute's name as in the example provided.

However, I'm focusing more on changing the attribute's value.

So building on the example provided, I would like to achieve the following...

if <foobar c="a"/> and <barfoo c="b"/>

then output

<foobar c="y"/>
<barfoo c="z"/>

Any thoughts on how this can be done?

k5tm · Nov 14, 2007

Yes, use the <xsl:attribute> element in the template that matches the c attribute, along the lines of:

Code:

<xsl:template match="foobar/@c">
   <xsl:attribute name="c">
   <xsl:text>y</xsl:text>
   </xsl:attribute> 
</xsl:template>
<xsl:template match="barfoo/@c">
   <xsl:attribute name="c">
   <xsl:text>z</xsl:text>
   </xsl:attribute> 
</xsl:template>

[small]Warning: typed, not tested[/small]

Since I am not aware of what your actual transformation rules might be, all I can provide is this hint.

Tom Morrison

http://www.liant.com

Tek-Tips is the largest IT community on the Internet today!

Members share and learn making Tek-Tips Forums the best source of peer-reviewed technical information on the Internet!

XSLT to copy all elements and attributes with modifications

Jake32

Programmer

k5tm

Programmer

Jake32

Programmer

k5tm

Programmer

Similar threads

Part and Inventory Search

Sponsor