XSL - 3 column table, fill 2 cells depending on type or fill all 3

[dseaver]

I have a table where either 2 or 3 columns are going to be filled, but there are 2 types of nodes filling them. The first two columns are the first type (A) and the third column is the second type(A). The input into the row is either 2A, 1A 1B, or 2A 1B. I want B in the third column regardless. The first cell in the Table will always be populated. I have conditional labeling of the cells right now.

Here is the XSL so far for the cells

<xsl:for-each select="Child">
				<fo:table-cell border="1pt solid black">
					<xsl:if test="string(TypeA/@Number)">
						<fo:block> <xsl:value-of select="Name"/></fo:block>
						<fo:block><xsl:value-of select="TypeA/@Number"/></fo:block>

					</xsl:if>
					<xsl:if test="string(TypeB/@Number)">
						<fo:block> <xsl:value-of select="Name"/></fo:block>
						<fo:block><xsl:value-of select="TypeB/@Number"/></fo:block>
						
					</xsl:if>
				</fo:table-cell>
			</xsl:for-each>

And here is the XML structure

 <Parent>
- <Child>
  <Name>Cell A</Name> 
  <TypeA Number="6" /> 
  </Child>
- <Child>
  <Name>Cell B</Name> 
  <TypeA Number="4" /> 
  </Child>
  </Parent>
- <Parent>
- <Child>
  <Name>Cell C</Name> 
  <TypeA Number="9" /> 
  </Child>
- <Child>
  <Name>Cell D</Name> 
  <TypeB Number="4" /> 
  </Child>
  </Parent>

THe output would be

|Column 1|Column 2| Column3|
|Cell A  |Cell B  |        |
|Cell C  |        |Cell D  |

Thanks!

 

[dseaver]

I figured the that part out by changing the code so that the cell tags were within the if statement and defined the cell for type be as <fo:table-cell column-number="3">. Is there a way to add the cell borders to each cell, even if it isnt populated? I have column borders, but cant get any row borders

 

[dseaver]

How come this does not work?

<fo:table-row border-width="1pt" border-style="solid">