pointer to constant char

[anxious7]

why this is not working ?

char* ptr= "Hello";
*ptr='s';
printf("%s\n",ptr);
[\code]

and this does

[code]
char a[] = "Hello";
char* ptr= &a;
*ptr='s';
printf("%s\n",ptr);
[\code]

 

[Salem]

Closer, but it's / not \ in the code tags.

> why this is not working ?
Because a "string" is stored in read-only memory. Being read-only, the OS will kill your program as soon as you try to modify it.

> and this does
Because what you have now is an initialised char array, which you can change all you want.


--
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.