bitwise logic operations

[neevor]

I am pretty new to c++ and have had a pretty easy time with it till i got to bitwise logic operations. I tried an example program out of a book I have and can't get it to work.
The code is:

#include <stdio.h>
#include <iostream.h>

int main(int nArg, char* nArgs[ ])
{
cout.setf ( ios::hex);
int nArg1;
cout << &quot;Enter arg1 as a four-digit hexadecimal;&quot;;
cin >> nArg1;

int nArg2;
cout << &quot;Enter arg2:&quot;;

int nArg2;
cout << &quot;Enter arg2:&quot;;
cin >> nArg2;
cout << &quot;nArg1 & nArg2 = 0x&quot;
<< (nArg1 & nArg2) << &quot;\n&quot;;
return 0;
}

when i put in a hex number like 0x1234 it will not let me put in the second argument and just gives me an answer.
could you please help?
thank you

 

[Skatanic]

You don't put in the 0x part. Just type in the 4 digit number in hex.

-Skatanic

 

[SeanGriffin]

The only Problem I see with your code it that there are two lines that are duplicated:

int nArg2;
cout << &quot;Enter arg2:&quot;;


once they where commented out it worde fine for me.

-Sean

 

[neevor]

I tried the suggestions and now it will take in both variables (thank you for helping with that) but it doesn't treat them as hex, if i put in 00ff first it won't take the second one, and if i put it in second (which i should not have to) it just uses the first one.

 

[kartiks]

Hi,

The variables that you have declared are all integers. So they can't accept hex values. Try accepting a character array for the hex value, drop the 1st 2 elements - which is 0x ( U can check to see if it is 0x ) , and then convert the hex to an Integer.

TO do the conversions to Integer , take the characters of the array and multiply it by 16^(their distance from the last element+1) and then add them up.

Now u have an int. Then u can perform integer operations on it and do the reverse process to convert it to hex.

I dont know if u can store values like ffff in int, if u can please someone tell me how to perform operations on it and what are the operational ranges and any other details.

Thankyou