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Thank you all for your inputs. I gave you all a "STAR" for your awsomeness.

That did the trick, adding "tail +2" to this command seems to have gotten rid of the leading blank line. Thanks a bunch!

I'm trying to capture the date/time portion of "ls -l" command as a file, but it puts a "blank line". How do I make it so that output file doesn't include a blank line? Example 1 (saved as a variable works good): var1=`ls -l /file1 | awk '{print $6,$7,$8}'` echo $var1 May 24 23:06 Example 2...

Thanks Khalid!

Anyone have any experience setting up ntp on AIX 5.3? Any tip will help. Thanks in advance.

I'm unable to move a file that I do not own but I'm part of the group the file is assigned to. Here's the scenario: userA owns file1 userA belongs to groupX userB belongs to groupX file1 has rights of 666 file1 is located in dir1 dir1 and dir2 are owned by userB dir1 and dir2 are group owned...

Thanks for your input DukeSSD. I was also leaning towards Virtual Ethernet Adapter method. fyi: there are two frames connected via a switch used to connect the two frames to be on one subnet.

I'm trying to configure NIM Master server with 30 clients on Virtual Ethernet Adapter network because the current network setup will not work with NIM for me (bootp can't find the master). Probably need to create a new network to get it to work. My environment is 2 P5-590's (connected via...

Thanks Annihilannic! It worked just as you explained. A big star for you! pdtak

Annihilannic, Yes, it worked just as you said. Your help is greatly appreciated. A big star for you. pdtak.

PHV, It works as a one liner, but I get an error when I put it in a script: #!/usr/bin/ksh ssh server1 awk -F":" '$1!~/^[a-z][0-9][0-9][0-9][0-9]$/{print $1}' /etc/passwd Syntax Error The source line is 1. The error context is >>> !~ <<< awk: 0602-540 There is a...

That worked. You are the best PHV! Thanks!

I need help with a script to find only users that starts with a alpha character followed by 4 digits (ie. a9999). Here's what I did so far (not working): #!/usr/bin/ksh cat /etc/passwd | awk -F: '{print $1}' | while [[ $MORE -ge 1 ]] do read USER if [ len(USER) == 5 ] then...

Thank you both for your input. I'll incorporate them into my script and see which works better.

I have two files that contains just file names. The first files has the nfs mount points (ie. /mnt, /nfs1, etc.) Second file has long file names (ie. /usr/bin/perl, /nfs1/file1, etc.) I want the third file to contain only the non-nfs mounted files. Example: file1: /mnt /nfs1 /nfs2 file2...

You were right feherke, it worked when I took out the echo command. PHV, your simplied version worked too. You guys really know your stuff! Thanks a lot!

Sorry, I substituted your printf command, but it didn't work... same output display. I think because I'm writing to an output file it's not taking \t in the printf command... any other ideas? Thanks PHV.

I'm trying to line up (align) output from "ls -l". I have the following awk command in a script that writes to a file (INFILE has bunch of file names): #!/bin/sh for LINE in `cat ${INFILE}` do echo `ls -l $LINE | awk '{printf ("%s %s:%s \t %s\n",$1, $3, $4, $9) }'` >> ${FORMATTED}...

Thanks PHV! Is it possible to echo the filename as well?

I need to find all occurrences of a particular string "Error code 27" from the whole server? I also need the file name associated with it. I tried the following command, but I only got the results from the current directory: > grep "Error code 27" * I need to go to all sub-directories and...