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How to read from a string into 8-byte integer?
Another update -- Just realized now that my error was not being caused by anything related to the integer*8 declaration or the read() function itself. I had a minor indexing problem on the do i = 0,(9-x) within the lexicographic sorting portion of the code which simply needed to have a -1 added...- MBFerguson
- Post #4
- Forum: Fortran
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How to read from a string into 8-byte integer?
Hello mikrom, I am using the following compiler version: $ gfortran --version GNU Fortran (GCC) 11.2.0 I am not necessarily tied down to this specific compiler, although I don't understand why a more recent version would have problems a previous version doesn't have. Here is my entire source...- MBFerguson
- Post #3
- Forum: Fortran
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How to read from a string into 8-byte integer?
I have the following 8-byte integer defined as follows: integer*8 :: strINT = 0 And an allocatable string defined using character(:), allocatable :: str str = "9876543210" I'm trying to set the strINT variable using the read function read(str,*) strINT However, this gives the following...- MBFerguson
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- Replies: 5
- Forum: Fortran
