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alan147 (TechnicalUser)
1 Jul 12 12:31
Good afternoon

Is there a way to compare two numbers such that if the two are within 5 of each other the result is true but if the difference is greater the 6 then the result is false?

Thanks

Alan
Helpful Member!  feherke (Programmer)
1 Jul 12 12:50
Hi

CODE --> (ba|k)sh

(( difference=first-second )) # calculate the difference
(( ${difference/#-}<6 )) && echo 'YES' || echo 'no' # test the difference's absolute value 
Tested with Bash and MKsh.

For a working test example you may check this in Bash ( sorry, to lazy to write Ksh-friendly while loop now ) :

CODE --> bash

for ((i=-5;i<=5;i++)); do for ((j=-5;j<=5;j++)); do (( d=i-j )); printf '%3d %3d %s\n' "$i" "$j" "$( (( ${d/#-}<6 )) && echo 'YES' || echo 'no' )"; done; done 

Feherke.
http://feherke.github.com/

alan147 (TechnicalUser)
1 Jul 12 13:12
Feherke

That's great just what I wanted to do.

Thanks

Alan

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