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Home > Forums > Programmers > Web Development > PHP Forum

ajax - hidden inputHelpful Member!(2) 

thread434-1686321
Read More Threads Like This One
ag1060 (Programmer)
20 Jun 12 13:02
Hello coders,

I'm trying to create this ajax live search and I need to pass on 'hidden' input type...

So here's where i'm stuck:

CODE

$query = $db->query("SELECT pid, ptitle FROM projects WHERE ptitle LIKE '$queryString%' LIMIT 10");
if($query) {

while ($result = $query ->fetch_object()) {

echo <<<EOF
<li onClick="fill('$result->ptitle');">$result->ptitle</li>
<input type="hidden" name="pid" value=$result->pid>


EOF;
}
}

So basically I need to pass the hidden input "pid" to each value. The 'fill' puts the data into the textbox and that part works fine. But I also need to add the hidden input 'pid'...So far it just displays the same 'pid' rather than the correct one depending on the result. I'm sure there's a better way to approach this. any clue?

thanks in advance.
Helpful Member!  jpadie (TechnicalUser)
20 Jun 12 13:17
no reason that I can see why the value would be the same for each <li>. The code looks correct (ish - see below). i suspect that the value in the database table must be the same so check the underlying data.

and change the code to the below

CODE

echo <<<EOF

<li onClick="fill('{$result->ptitle}');">{$result->ptitle}</li> <input type="hidden" name="pid" value="{$result->pid}" />

EOF;

but I can't really see why you're doing this. why not just add the pid (if you need it) to the fill() method?
vacunita (Programmer)
20 Jun 12 13:32
I'd say calling every hidden input "pid" will likely cause some confusion when accessing the actual value.

I agree with jpadie, that passing the pid value to the fill function may be a better choice.

----------------------------------
Phil AKA Vacunita
----------------------------------
Ignorance is not necessarily Bliss, case in point:
Unknown has caused an Unknown Error on Unknown and must be shutdown to prevent damage to Unknown.

Web & Tech

ag1060 (Programmer)
20 Jun 12 13:37
Hello,

Thanks for replying. It does work when I put on the 'fill' part. I don't want the 'pid' to be displayed to the user since I only want the user to select the result. Here's a screenshot of what I have:

http://s8.postimage.org/e3g2bjvz7/ajax.png


So basically I want the 'pid' to be hidden so the user would only see the title they have chosen. This way I could just fetch the pid from the table and display.

Helpful Member!  vacunita (Programmer)
20 Jun 12 13:43
So what's the problem?

Just passing the value to the fill function won't show the value anywhere but in the function call.

----------------------------------
Phil AKA Vacunita
----------------------------------
Ignorance is not necessarily Bliss, case in point:
Unknown has caused an Unknown Error on Unknown and must be shutdown to prevent damage to Unknown.

Web & Tech

ag1060 (Programmer)
20 Jun 12 13:46
I will try that. This should work :)
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