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vfp6 - getting Windows Title for an image. 1
- Thread starter wetton
- Start date
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1
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Found on tek-tips earlier:
basically works like this:
Just give file a Title then look what position in will came up...
basically works like this:
Code:
Dimension arrHeaders(35)
objShell=CreateObject("Shell.Application")
objFolder=objShell.Namespace("c:\tmp")
* Array of possible file properties (35)
For i = 0 to 34
arrHeaders(i+1) = objFolder.GetDetailsOf(objFolder.Items, i)
Next
* create object of an existing file
objFolderItem=objFolder.ParseName('Image3.jpg')
* print all 35 properties
For i = 0 to 34
? i ,arrHeaders(i+1), ": " , objFolder.GetDetailsOf(objFolderItem, i)
NextJust give file a Title then look what position in will came up...
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