Get lines either side of a grep 2

stackdump · Jan 12, 2006

I want to grep a file (the output of lmstat -a) and see the matching line plus the next few.

The first part is easy; lmstat -a | grep -i xyz

but how can I get the next few lines? or maybe the subsequent lines up until the occurrence of a different pattern?

In regex this would be something like

lmstat -a | grep -ie 'users of xyz.*users'

but grep wont do singleline mode.

p5wizard · Jan 12, 2006

I'm not familiar with lmstat output (can you provide a sample output file?), but perhaps you can use

grep -ip xyz

for this (paragraph containing xyz - case insensitive).

The default para separator is empty line, but you can specify another parasep. See grep man page for more info.

HTH,

p5wizard

olded · Jan 12, 2006

Take a look at this link:

http://www.unixreview.com/documents/s=9455/ur0412b/ur0412b.html

PHV · Jan 12, 2006

You may try something like this:
lmstat -a | awk '/pattern1/,/pattern2/'

Hope This Helps, PH.
Want to get great answers to your Tek-Tips questions? Have a look at FAQ219-2884 or FAQ181-2886

stackdump · Jan 12, 2006

Thanks guys, but I'm still having problems...

This is a fragment of "lmstat -a".

Code:

Users of 44500:  (Total of 4 licenses issued;  Total of 1 license in use)

  "44500" v1.000, vendor: accslmd
  floating license

    geoff sol1 wsacdc.dom:0.0 (v4.400) (gemini/7200 790), start Thu 1/12 16:29

Users of 33301:  (Total of 6 licenses issued;  Total of 0 licenses in use)

Users of 88800:  (Total of 6 licenses issued;  Total of 2 licenses in use)

  "88800" v1.000, vendor: accslmd
  floating license

    jodie sol4 wsacwb.dom:0.0 (v4.400) (gemini/7200 685), start Tue 1/10 13:14
    geoff sol1 wsacdc.dom:0.0 (v4.400) (gemini/7200 566), start Thu 1/12 13:05

Users of 44700:  (Total of 6 licenses issued;  Total of 1 license in use)

  "44700" v1.000, vendor: accslmd
  floating license

    geoff sol1 wsacdc.dom:0.0 (v4.400) (gemini/7200 490), start Thu 1/12 16:19

Users of 140:  (Total of 6 licenses issued;  Total of 0 licenses in use)

Users of 141:  (Total of 4 licenses issued;  Total of 0 licenses in use)

Users of 142:  (Total of 6 licenses issued;  Total of 0 licenses in use)

Users of 142 means users of productName 142. If the "users" is >0 then underneath, it lists the users.

I want to get a list of products in use; productName User

So this would be;

44500 geoff
88800 jodie geoff
44700 geoff

PHV · Jan 12, 2006

A starting point:
lmstat -a | awk '
$1=="Users" && $11>0{
u=$3;n=$11;printf "%s",u
for(i=0;i<4;++i)getline
for(i=0;i<n;++i){getline;printf " %s",$1}
printf "\n"}
' > /path/to/output

Hope This Helps, PH.
Want to get great answers to your Tek-Tips questions? Have a look at FAQ219-2884 or FAQ181-2886

stackdump · Jan 12, 2006

Thanks,

that'll get me most of the way there.

p5wizard · Jan 13, 2006

Not exactly how you want the output, and awk is better suited for this - see PHV's solution, but grep -p and sed can produce this:

Code:

lmstat -a | grep -p"Users of " vendor | sed '/floating/d; /^$/d; s/^ *//; s/ .*$//; s/"//g'
44500
geoff
88800
jodie
geoff
44700
geoff

HTH,

p5wizard

stackdump · Jan 13, 2006

Also a neat solution!

Thanks dudes.

Have a star.

Ghodmode · Jan 15, 2006

My grep command doesn't have a -p argument [sadeyes]

Try this FAQ for another method: How to view lines before and after a grep result.

--
-- Ghodmode

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Get lines either side of a grep 2

stackdump

Technical User

p5wizard

IS-IT--Management

olded

Programmer

PHV

MIS

stackdump

Technical User

PHV

MIS

stackdump

Technical User

p5wizard

IS-IT--Management

stackdump

Technical User

Ghodmode

Programmer

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