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Home > Forums > Programmers > DBMS Packages > Microsoft: Access Modules (VBA Coding) > FAQs

Microsoft: Access Modules (VBA Coding) FAQ

Error Resolution

DoCmd.OutputTo causes run-time error 2024 or 2302
faq705-6303
Posted: 19 May 06

After sweating over this problem and not getting anywhere with search, I found the solution is almost as simple as MS describes in their Knowledge Base article.  

M$'s example to duplicate the problem

CODE

Sub OutputSnapshot()
   DoCmd.OutputTo acOutputReport, "Alphabetical List of Products", acFormatSNP, "C:\My Documents\", True
End Sub
    

What they don't explain is you need to add the file name to the OutPutFile argument.  You can either hard code the name, or you can use a variable if you want to assign different names each time your run the code.  In this example, I change the name of the .snp file by assigning the current date to the name.

CODE

Sub OutputSnapshot()
Dim myFile as String

     myFile = "SomeName" & Format(Date(),"mmddyy") & ".snp"
   DoCmd.OutputTo acOutputReport, "Alphabetical List of Products", acFormatSNP, "C:\My Documents\" & myFile, True
End Sub
One hint is to make sure you don't have any invalid characters in the file name which is why my example takes the / out of the date format.
HTH

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